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x^2-30x=8800
We move all terms to the left:
x^2-30x-(8800)=0
a = 1; b = -30; c = -8800;
Δ = b2-4ac
Δ = -302-4·1·(-8800)
Δ = 36100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{36100}=190$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-190}{2*1}=\frac{-160}{2} =-80 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+190}{2*1}=\frac{220}{2} =110 $
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